For two numbers, a & b, define the operation, "&" by: a&b = 2a(a-b)?

a). Find the value of 3 %26amp; 2


b). For what exact values of x is: 4 %26amp; x=42?


c). For what exact values of x is: x %26amp; 4 =42?

For two numbers, a %26amp; b, define the operation, "%26amp;" by: a%26amp;b = 2a(a-b)?
a%26amp;b = 2a(a-b)


3%26amp;2 = 2*3(3-2)


3%26amp;2 = 6*1


3%26amp;2 = 6


So %26amp; = *





4x = 42


X=42/4


X= 10.5





x4 = 42


x= 42/4


x= 10.5
Reply:Somthing seems to be missing or maybe I am missing the boat here
Reply:a+b=2(a-b) =%26gt; a+b/a-b =2


4+x=42


x=42-4


x=38


or


4x=42 =%26gt;x=42/4 =%26gt;10.5
Reply:Do y'all ever think of reading the question?





The solution method is simple, just plug the numbers into the formula you are given, and solve. So:





a: 3%26amp;2=2*3(3-2)=6





b: 2*4(4-x)=42


32-8x=42


-8x=10


x = -10/8 = -5/4





c: 2*x(x-4)=42


x(x-4)=21


x²-4x=21


x²-4x+4=25


(x-2)²=25


x-2=±5


x=-3 or x=7